Question

What is the volume of a sphere with a diameter of 2.2 ft, rounded to the nearest tenth

of a cubic foot?

Answer 1

V≈5.58ft³ d=2.2 ft

Explanation:

V=4 3πr3

d=2r

Solving for V

V=1 6π d3 =1 6·π·2.23≈5.57528ft³

Hope this helps! :D

Answer 2

5.6 ft

Explanation:

\text{Volume of a Sphere:}

Volume of a Sphere:

V=\frac{4}{3}\pi r^3

V=

3

4

​

πr

3

\text{radius} = \frac{\text{diameter}}{2} = \frac{2.2}{2}=1.1

radius=

2

diameter

​

=

2

2.2

​

=1.1

feet

\text{Plug in:}

Plug in:

\frac{4}{3}\pi (1.1)^3

3

4

​

π(1.1)

3

5.57527976257