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Suppose we have a 4096 byte byte-addressable memory that is 32-way high-order interleaved, what is the size of the memory address module offset field?

a. 10

b. 7

c. 5

d. 4

1 Answer

1 vote

Answer:

7

Step-by-step explanation:

Given that :

Byte-addressable memory = 4096

Order = 32

Rwqritying such that they have the same base ;

4096 = 2^12

32 = 2^5

2^12 - 2^5

12 - 5 = 7

User MrPotatoHead
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