Question

Part A )a painter leans a ladder up against a building. The base of the ladder is placed 7 feet from the building to reach a height of 24 feet. How long is the ladder

Part B) The painter uses the same ladder from part A, but now needs to reach a height of 19 feet.How far away does the base of the ladder need to be placed from the building? ​

Answer 1

Part A). 25 feet

Part B). 16.25 feet

Explanation:

Part A). By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

AC² = (24)² + 7²

AC² = 576 + 49

AC = √625

= 25 feet

Part B). By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

(25)² = (19)² + x²

625 = 361 + x²

x² = 625 - 361

x = √264

x = 16.25 feet