172k views
1 vote
Three friends said their heights were 5 and start fraction 13 over 30 end fraction feet, 5 and one-sixth feet, and 5 and start fraction 68 over 90 end fraction feet. Put the heights of the friends in order from least to greatest. A. 5 and start fraction 68 over 90 end fraction < 5 and start fraction 13 over 30 end fraction < 5 and one-sixth B. 5 and start fraction 13 over 30 end fraction <5 and one-sixth <5 and start fraction 68 over 90 end fraction C. 5 and one-sixth <5 and start fraction 68 over 90 end fraction < 5 and start fraction 13 over 30 end fraction D. 5 and one-sixth <5 and start fraction 13 over 30 end fraction< 5 and start fraction 68 over 90 end fraction

User Boken
by
8.8k points

2 Answers

3 votes

Answer:

The answer is 5235 5521 2356

Explanation:

User Jxgn
by
8.4k points
4 votes

Answer:


5(1)/(6) < 5(13)/(30) < 5(68)/(90)

Explanation:

Represent the friends with A, B and C


A = 5(13)/(30)


B = 5(1)/(6)


C = 5(68)/(90)

Required

Order from least to highest

First, we convert the given parameters to decimal


A = 5(13)/(30)


A = 5 + (13)/(30)


A = 5 + 0.43


A = 5.43


B = 5(1)/(6)


B = 5 + (1)/(6)


B = 5 + 0.17


B = 5.17


C = 5(68)/(90)


C = 5 + (68)/(90)


C = 5 + 0.76


C = 5.76

So, we have:


A = 5.43
B = 5.17
C = 5.76

Order from least to greatest


B = 5.17
A = 5.43
C = 5.76

Replace them with the original values


B = 5(1)/(6)
A = 5(13)/(30)
C = 5(68)/(90)

Hence, the correct order is:


5(1)/(6) < 5(13)/(30) < 5(68)/(90)

User Eric Warmenhoven
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories