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How many molecules are in a 189 g sample of carbon tetrabromide, CBr4?
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3 votes
How many molecules are in a 189 g sample of carbon tetrabromide, CBr4?

User Robert Audi
by
4.5k points

2 Answers

5 votes
Answer:

3.4321229*10^23 molecules.

Step-by-step explanation:

1 mole of CBr4 contains 6.0221409*10^23 molecules (Avogadro's Number).

The molar mass of this compound is 12.011 + 4(79.904)

= 331.627 g.

So the answer is (189/ 331.627) * 6.0221409*10^23

= 3.4321229*10^23 molecules.
User Oleksandr Veremchuk
by
4.8k points
3 votes
Answer:
3.4321229*10^23 molecules.
Step-by-step explanation:
1 mole of CBr4 contains 6.0221409*10^23 molecules (Avogadro's Number).
The molar mass of this compound is 12.011 + 4(79.904)
= 331.627 g.
So the answer is (189/ 331.627) * 6.0221409*10^23
= 3.4321229*10^23 molecules.
User Abdelrahman Eid
by
4.7k points
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