Question

What is the standard form of –23f² + f/2 = –√3?​

Answer 1

y = -23f^2 + 1/2f + √3

Explanation:

Standard form: y = ax^2 + bx + c

x = f

a = -23

b = 1/2

c = √3

–23f² + f/2 = -√3

-23f² + f/2 + √3 = 0

y = -23f^2 + f/2 + √3

y = -23f^2 + 1/2f + √3