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Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Remember: cal=m*deltaT

(WRITE THE WORK!/Give explanation.)

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Answer:

Q = 12540 J

Step-by-step explanation:

It is given that,

Mass of water, m = 50 mL = 50 g

It is heated from 0 degrees Celsius to 60 degrees Celsius.

We need to find the energy required to heat the water. The formula use to find it as follows :


Q=mc\Delta T

Where c is the specific heat of water, c = 4.18 J/g°C

Put all the values,


Q=50* 4.18* (60-0)\\Q=12540\ J

So, 12540 J of energy is used to heat the water.

User Supreeth Meka
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