Question

2b-3/b-2 = 3b/b+2 ... Solutions by cross multiplying

ANSWER > 1, 6
- Neither 1 or 6 are extraneous

Answer 1

Explanation:

(2b-3)/(b-2)(b+2) = 3b(b-2)/(b+2)(b-2)

2b²+4b-3b-6/b²-4=3b²-6b/b²-4

2b²+b- 6= 3b²-6b

move square to square unknown to unknown

-b²+7b-6/b²-4

i also dk this is true or false