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What is the area of aregular hexagon with side length of 10units square?


User Mckenzm
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2 Answers

13 votes
13 votes

Answer:

150 sqrt 3 = 259.8076 units^2

Explanation:

Interior angles of hexagon = 120 degrees ....now look at the Right 1/2 of the hexagon... see illustration....this is a trapezoid...

One base is 10 units

the other labelled 'base' is

10 cos 60 + 10 cos 60 + 10 = 20 units

the height of this trapezoid is 10 sin 60 = 10 * sqrt(3)/2 = 5 sqrt(3)

the area of this trapezoid is then 1/2 ( 10+ 20) * 5 sqrt (3) = 75 sqrt 3

there are TWO of these trapezoids in the hexagon so total area is then

2 * 75 sqrt 3

150 sqrt 3

What is the area of aregular hexagon with side length of 10units square? ​-example-1
User ForFunAndProfit
by
3.0k points
13 votes
13 votes

Answer:

h ≈ 259.81

Explanation:

i used the hexagon calculator

What is the area of aregular hexagon with side length of 10units square? ​-example-1
User Wds
by
3.0k points