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Kathryn decides to take her dog for a walk one day. Her dog tries pulling on her with a force of 15N. Kathryn pulls back with force of 20N. What is the net force?
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Kathryn decides to take her dog for a walk one day. Her dog tries pulling on her with a force of 15N. Kathryn pulls back with force of 20N. What is the net force?

User Dimitre Novatchev
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1 Answer

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Assuming both forces act horizontally, the net force is in Kathryn's direction with a magnitude of 5 N.

If "towards Kathryn" is taken the be the positive direction, then the net force is

∑ F = 20 N - 15 N = 5 N

User NewTech Lover
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