Answer:
C) 9.4 m/s
Step-by-step explanation:
= Mass of moving car = 1200 kg
= Initial velocity of moving car = 21.1 m/s
= Mass of stationary car = 1500 kg
= Initial velocity of stationary car = 0
v = Velocity of the combined cars
As the momentum in the system is conserved we have
![m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=(m_1u_1+m_2u_2)/(m_1+m_2)\\\Rightarrow v=(1200* 21.1+1500*0)/(1200+1500)\\\Rightarrow v=9.378\approx 9.4\ \text{m/s}](https://img.qammunity.org/2021/formulas/physics/high-school/7of89xmpk9ergs7noi2rj081qvkljttxbi.png)
The velocity of the combined mass is 9.4 m/s.