Question

A car accelerates from rest at a rate of 3 m/s² for 4 seconds. How far did the car travel?

PLEASE help fasttt

Answer 1

Distance= distance(initial)+v(initial)*t+0.5at^2
D=0+0*4+0.5*3*4^2
D=24 m

Answer 2

24m

Step-by-step explanation:

Given parameters:

Initial velocity = 0m/s

Acceleration = 3m/s²

Time = 4s

Unknown:

Distance covered = ?

Solution:

To solve this problem, we apply the right motion equation:

S = ut +
`(1)/(2)`at²

S is the distance

u is the initial velocity

t is the time taken

a is the acceleration;

S = (0 x 4) +
`(1)/(2)` x 3 x 4²

S = 24m