Question

4. Chemical formula, mg (Cl0₃)2

a) calculate the number of moles for 3.24g, Mg (Cl03)2
b) calculate the molarity of mg (Cl03)2 if all of it were dissolved in
5.08 L distilled water.​

Answer 1

0.017mole

0.0033M

Step-by-step explanation:

Given parameters:

Formula of the compound:

Mg(ClO₃)₂

Mass of the sample = 3.24g

Unknown:

Number of moles of the sample = ?

Molarity = ?

Solution:

The number of moles of any substance is given as:

Number of moles =
`(mass)/(volume)`

Molar mass of Mg(ClO₃)₂ = 24 + 2[35.5 + 3(16)] = 191g/mol

Number of moles =
`(3.24)/(191)` = 0.017mole

Molarity is the number of moles of a solute in a solution:

Molarity =
`(number of moles )/(volume)`

Volume given = 5.08L

Molarity =
`(0.017)/(5.08)` = 0.0033M