Question

Kindly solve this question 6 too !!

Answer 1

`x=1`

Explanation:

`~~~~~x = \frac{1}{2 - \frac 1{2-(1)/(2-x)}}\\\\\\\implies x = \frac{1}{2 - \frac 1{(4-2x-1)/(2-x)}}\\\\\\\implies x= (1)/(2 - (2-x)/(3-2x))\\\\\\\implies x = (1)/((6-4x-2+x)/(3-2x))\\\\\\\implies x = (3-2x)/(4-3x)\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1`