Question

What is an equation of the line that passes through the point (2, -3) and is

perpendicular to the line 2x + 5y = 10?

Answer 1

y = 5/2x - 8

Explanation:

convert to y = mx + b

2x + 5y = 10

5y = -2x + 10

y = -2/5x + 2

flip the slope to 5/2

y = 5/2x + 2

plug in (2, -3)

-3 = 5/2(2) + b

-3 = 5 + b

-8 = b

y = 5/2x - 8