Answer:
The kinetic coefficient of friction of the sled on the snow is 0.05
Step-by-step explanation:
The given parameters are;
The weight of the sled Jill is pulling, W = 200 N
The force with which Jill is pulling the the sled = 10 Newtons
The nature of the speed with which the sled is pulled = Constant speed
Therefore, given that the only opposing force to the pulling of the sled = The force of kinetic friction, we have;
The force with which Jill is pulling the the sled = 10 Newtons = The force of kinetic friction,
![F_k](https://img.qammunity.org/2021/formulas/mathematics/high-school/eqi9pum2ppniyvuepe3w0ik6xuurr8xvag.png)
The force of kinetic friction = The weight of the sled, W × The kinetic coefficient of friction of the sled on the snow,
![\mu _k](https://img.qammunity.org/2021/formulas/physics/high-school/a1jg116ekb2lb2vnnhuc1utcyssgl95o9a.png)
= W ×
![\mu _k](https://img.qammunity.org/2021/formulas/physics/high-school/a1jg116ekb2lb2vnnhuc1utcyssgl95o9a.png)
=
/W = 10 N/(200 N) = 0.05
The kinetic coefficient of friction of the sled on the snow =
= 0.05.