Question

7x-5=8(x*3) what value of x makes this equation true

Answer 1

Explanation:

Question:-

Solve for x

`\\ \tt{:}\leadsto 7x-5=8(x+3)`

SOLUTION:-

`\\ \tt{:}\leadsto 7x-5=8(x+3)`

`\\ \tt{:}\leadsto 7x-5=8x+24`

`\\ \tt{:}\leadsto 7x-8x=24+5`

`\\ \tt{:}\leadsto -x=29`

`\\ \tt{:}\leadsto x=29`

Answer 2

The given equation is:

`\displaystyle 7x-5=8(x+3)`

The first step you need to do is open the parentheses and distribute the 8 to x+3. It will be 8 times x and 3 times x.

`8(x+3)=8 * x+ 8 * 3\\\\8 * x=8x\\8 * 3=24`

`8(x+3) \rightarrow 8x+24`

Rewrite the equation:

`7x-5=8x+24`

Now you need to move one of the variables to the other side.

If you move 7x to the other side, then:

You can move the variable by doing the opposite of it. Since 7x is positive, you can move it by subtracting 7x, which is negative. Subtract 7x on both sides:

`7x-5-7x=8x+24-7x\\-5=x+24`

Now you need to leave x alone. x is being added to 24, so remove it by subtracting both sides by 24. Remember that when you're subtracting from a negative number, you're actually adding while keeping the negative sign.

`-5-24=x+24-24`

Subtract:

`\bf-29=x`

If you move 8x to the other side, then:

8x is positive, so you can move it by subtracting 8x, which is negative. Subtract 8x on both sides:

`7x-5-8x=8x+24-8x\\-x-5=24`

You need to leave the variable alone, so move -5 to the other side. You can do this by adding 5 to both sides.

`-x-5+5=24+5\\-x=29`

Lastly, x is negative, but you're looking for the value of positive x. Divide both sides by -1 to remove the negative sign.

`\displaystyle (-x)/(-1) =(29)/(-1)`

Remember that a positive number divided by a negative number is negative. Divide:

`\bf x=-29`

The answer to your question is x = -29.