Question

If two charged objects in a laboratory are brought to a distance of 0.22 meters away from each other. What is

the force between the spheres is 4,550 N and the charge on one object is 9.9×10–5 C

Answer 1

`q_2=2.47* 10^(-4)\ C`

Step-by-step explanation:

The charge on one object,
`q_1=9.9* 10^(-5)\ C`

The distance between the charges, r = 0.22 m

The force between the charges, F = 4,550 N

Let q₂ is the charge on the other sphere. The electrostatic force between two charges is given by the formula as follows :

`F=(kq_1q_2)/(r^2)\\\\q_2=(Fr^2)/(kq_1)\\\\q_2=(4550* (0.22) ^2)/(9* 10^9* 9.9* 10^(-5))\\\\q_2=2.47* 10^(-4)\ C`

So, the charge on the other sphere is
`2.47* 10^(-4)\ C`.