Question

−3x(4x² − 81) (x² + 64) = 0

Answer 1

Answer:
`x=0,x=-(9)/(2), x=(9)/(2)`

Explanation:

`-3x(4x^2-81)(x^2+64)=0\\`

multiply the terms together

`-12x^5-525x^3+15552x=0`

factor left side of the equation

`3x(-x^2-64)(2x+9)(2x-9)=0`

set factors equal to 0

`x=0,x=-(9)/(2), x=(9)/(2)`