−3x(4x² − 81) (x² + 64) = 0

asked Mar 21, 2023 109k views

12 votes

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7 votes

Answer:
x=0,x=-(9)/(2), x=(9)/(2)

Explanation:

$-3x(4x^2-81)(x^2+64)=0\\$

multiply the terms together

-12x^5-525x^3+15552x=0

factor left side of the equation

3x(-x^2-64)(2x+9)(2x-9)=0

set factors equal to 0

x=0,x=-(9)/(2), x=(9)/(2)

Drk answered Mar 28, 2023

by Drk

6.1k points

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