Question

How many moles of MgCO3 are in 2.57g of MgCO3?

Answer 1

To find the number of moles of MgCO3 in 2.57g of MgCO3, divide the mass by the molar mass of MgCO3.

Step-by-step explanation:

To find the number of moles of MgCO3 in 2.57g of MgCO3, we need to use the molar mass of MgCO3. The molar mass of MgCO3 is made up of the atomic masses of Mg (24.31 g/mol), C (12.01 g/mol), and 3 O atoms (16.00 g/mol each). Adding these up, we get a molar mass of 84.31 g/mol for MgCO3.

To convert grams to moles, we can use the equation:

Moles = Mass / Molar Mass

Using this equation, we can find the number of moles:

Moles of MgCO3 = 2.57g / 84.31 g/mol = 0.0305 mol

Answer 2

0.0305 moles of MgCO₃

Step-by-step explanation:

In order to solve this problem, we first need to calculate the molecular weight of MgCO₃:

• MgCO₃ MW = Atomic mass Mg + Atomic mass C + (Atomic mass O)*3

• MgCO₃ MW = 24.3 + 12 + 16*3 = 84.3 g/mol

Finally we divide the mass by the molecular weight, to calculate the number of moles:

• 2.57 g MgCO₃ ÷ 84.3 g/mol = 0.0305 moles.