Answer:
Explanation:
To find possible approximations for the system of linear equations, we need to look for points that satisfy both equations. Let's check the given points:
(1.9, 2.5):
For the first equation:
y = -7/4 * x + 5/2
y = -7/4 * 1.9 + 5/2 ≈ -1.225 + 2.5 ≈ 1.275
For the second equation:
y = 3/4 * x - 3
y = 3/4 * 1.9 - 3 ≈ 1.425 - 3 ≈ -1.575
The point (1.9, 2.5) does not satisfy either equation.
(2.2, -1.4):
For the first equation:
y = -7/4 * x + 5/2
y = -7/4 * 2.2 + 5/2 ≈ -3.85 + 2.5 ≈ -1.35
For the second equation:
y = 3/4 * x - 3
y = 3/4 * 2.2 - 3 ≈ 1.65 - 3 ≈ -1.35
The point (2.2, -1.4) satisfies both equations.
(2.2, -1.35):
For the first equation:
y = -7/4 * x + 5/2
y = -7/4 * 2.2 + 5/2 ≈ -3.85 + 2.5 ≈ -1.35
For the second equation:
y = 3/4 * x - 3
y = 3/4 * 2.2 - 3 ≈ 1.65 - 3 ≈ -1.35
The point (2.2, -1.35) satisfies both equations.
(1.9, 2.2):
For the first equation:
y = -7/4 * x + 5/2
y = -7/4 * 1.9 + 5/2 ≈ -1.225 + 2.5 ≈ 1.275
For the second equation:
y = 3/4 * x - 3
y = 3/4 * 1.9 - 3 ≈ 1.425 - 3 ≈ -1.575
The point (1.9, 2.2) does not satisfy either equation.
(1.9, 1.5):
For the first equation:
y = -7/4 * x + 5/2
y = -7/4 * 1.9 + 5/2 ≈ -1.225 + 2.5 ≈ 1.275
For the second equation:
y = 3/4 * x - 3
y = 3/4 * 1.9 - 3 ≈ 1.425 - 3 ≈ -1.575
The point (1.9, 1.5) does not satisfy either equation.
The two possible approximations for this system are (2.2, -1.4) and (2.2, -1.35).