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2 votes
1-4y^2 = 0
Solve the equation

2 Answers

9 votes

Step-by-step explanation:


1-4y^2=0\\1^2-(2y)^2=0\\(1-2y)(1+2y)=0\\


1-2y=0 or
1+2y=0\\


2y=1 or
2y=-1\\


y= (1)/(2) or
y=(-1)/(2)

P/s:
A^2-B^2=(A-B)(A+B)

Ok done. Thank to me :>

User Jacopofar
by
8.3k points
11 votes

Answer: y = 1/2 or y = -1/2

Step-by-step explanation:

First move the 1 to the side with the 0

-4y^2 = -1 // -1 because when you move a number to the other side of the equation you have to multiply -1

Then divide by -4 on each side

y^2 = 1/4

square root each side

|y| = 1/2 // sq rt y^2 becomes an absolute value because when you square root a square it automatically becomes an absolute value

so the answer would be y = 1/2 or -1/2

to check just put it into the equation as y. Both work.

User Luuk Schoenmakers
by
8.0k points

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