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David is having a cookout. Hot dogs and buns are sold based on the following quantities per package.

Item
Amount Per Package
Hot dog buns
12
Hot dogs
10
A
David thought that he would have to buy 12 packages of hot dog buns and 10 packages of hot dogs to have one bun for each hot dog.
What is the LEAST amount of each David would need to buy to have an equal number of hot dogs and buns?
David should buy 2 packages of buns and 2 packages of hot dogs,
David should buy 6 packages of buns and 5 packages of hot dogs.
с David should buy 5 packages of buns and 6 packages of hot dogs,
D David should buy 22 packages of buns and 22 packages of hot dogs
B

1 Answer

5 votes

Answer: Choice C) David should buy 5 packages of buns and 6 packages of hot dogs.

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Step-by-step explanation:

Focus on the hot dog buns for now

1 package = 12 hot dog buns

2 packages = 24 hot dog buns (multiply both sides by 2)

3 packages = 36 hot dog buns (multiply original equation by 3)

We can see that the multiples of 12 are being listed. So we have

12, 24, 36, 48, 60, 72, 84, ...

as the possible number of hot dog buns we could get if we buy 1,2,3... packages.

The possible number of hot dogs we can get are

10, 20, 30, 40, 50, 60, 70, 80, ...

which are multiples of 10. Simply add 10 to each item to get the next one.

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Considering these two sets

12, 24, 36, 48, 60, 72, 84, ...

10, 20, 30, 40, 50, 60, 70, 80, ...

what is the lowest common multiple? That would be 60 since it is found in both lists and it is the smallest in common.

The LCM of 12 and 10 is 60.

If he wanted 60 hot dog buns, then 60/12 = 5 packages of buns is what he needs.

If he wanted 60 hot dogs, then he needs 60/10 = 6 packages of hot dogs.

Therefore, David should buy 5 packages of buns and 6 packages of hot dogs. The answer is choice C.

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Side note: a different way to find the LCM is to multiply 10 and 12 to get 10*12 = 120. Then we divide by the GCF 2 getting 120/2 = 60.

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