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I NEED HELP!!!! WITH NUMBER 9, & 10??

I NEED HELP!!!! WITH NUMBER 9, & 10??-example-1
User Fix
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1 Answer

3 votes

Answer:

awnser one is 7 and question 2 is -10

Explanation:

−12−2−−55=? question one

In the first fraction, the negative numerator and negative denominator cancel each other.

Since the the second fraction is negative and you are subtracting, remove the negative sign and switch the operation to addition.

The equivalent equation is

122+55=?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(12/2, 5/5) = 10

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(122×55)+(55×22)=?

Complete the multiplication and the equation becomes

6010+1010=?

The two fractions now have like denominators so you can subtract the numerators.

Then:

60+1010=7010

Since 70 divided by 10 equals 7 then,

7010=7

Therefore:

−12−2−−55=7

Question 2

−81+6−3=?

In the second fraction, move the negative sign from the denominator to the numerator and the value remains the same.

The equivalent equation is

−81+−63=?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(-8/1, -6/3) = 3

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(−81×33)+(−63×11)=?

Complete the multiplication and the equation becomes

−243+−63=?

The two fractions now have like denominators so you can add the numerators.

Then:

−24+−63=−303

Since -30 divided by 3 equals -10 then,

−303=−10

Therefore:

−81+6−3=−10

Solution by Formulas

Apply the fractions formula for addition, to

−81+6−3

and solve

(−8×−3)+(6×1)1×−3

=24+6−3

=30−3

=−10

User Monojit Sarkar
by
5.2k points
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