Question

Using a launch speed of 40.0 m/s and any angle between 0 and 90 degrees, what would be the largest possible range for a projectile?

its 45

Answer 1

The largest possible range of the projectile is 163.27 m.

Step-by-step explanation:

Given;

launch speed, u = 40 m/s

angle of projection, θ; between 0⁰ and 90⁰

The range of a projection is given as;

`R = (u^2sin(2\theta ))/(g)`

The largest possible range will occur at 45 degrees angle of projection;

`R = (u^2sin(2\theta ))/(g) \\\\R = ((40)^2sin(2\ * \ 45^0 ))/(9.8)\\\\R = ((40)^2sin( 90^0 ))/(9.8)\\\\R = ((40)^2( 1 ))/(9.8) \\\\R = 163.27 \ m\\\\`

Therefore, the largest possible range of the projectile is 163.27 m.