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Graph the line with slope -3 passing through the point (3,-4)

User Notjustme
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Given:
\textsf{Slope = -3, Passes through (3, -4)}

Find:
\textsf{Equation in slope-intercept form}

Solution: The first step that we need to take is to plug the given values into the point-slope formula which would help us out since we have both the slope and a point. Using that we would then distribute on the right side of the expression and then subtract 4 from both sides which would isolate y.

Plug in the values


  • y - y_1 = m(x - x_1)

  • y - (-4) = -3(x - 3)

Distribute


  • y + 4 = (-3 * x) + (-3 * - 3)

  • y + 4 = -3x + 9

Subtract 4 from both sides


  • y + 4 - 4 = -3x + 9 - 4

  • y = -3x + 9 - 4

  • y = -3x + 5

Therefore, after plugging in the values and completing the rest of the steps we were able to determine that equation of the data provided would be
y = -3x + 5.

User Jayowend
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