Question

Three integers have a mean of 10, a median of 14 and a range of 12.
Find the three integers.

Answer 1

Let the numbers be a, b and c in order of size.
b is 14 as it is in the middle
c - a = 12 so c = a + 12
(a + b + c)/3 = 10
a + b + c = 30
a + 14 + (a + 12) = 30
2a + 26 = 30
2a = 30 - 26 = 4
a = 2
c = 2 + 12 = 14
So the three numbers are 2, 14 and 14