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Graph f(x)=3/2x+2. plz help

1 Answer

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Answer:

draw a line trough (2,3) and (0, 2)

Explanation:

f(x)=(3/2)x+2

so 3/2 is your slope and 2 is your y coordinate of y-intercept

pick any point to start for example (0, 0) and go slope=rise/run=3/2 and you will end-up at (2,3)

now you have a point (2,3) and a second the y-intercept (0,2)

draw a line trough those points

User Jankya
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