The frequency : a) 7.5 x 10¹⁴ /s
Further explanation
Radiation energy is absorbed by photons
The energy in one photon can be formulated as
![\large{\boxed{\bold{E\:=\:h\:.\:f}}}](https://img.qammunity.org/2021/formulas/chemistry/high-school/tyw4apt35c2k3rzs0sargeltryngqgxp2f.png)
Where
h = Planck's constant (6,626.10⁻³⁴ Js)
f = Frequency of electromagnetic waves (/s or Hz)
f = c / λ
c = speed of light
= 3.10⁸ m/s
λ = wavelength
The wavelength(λ) of purple light is 400 x 10⁻⁹ m, so the frequency :
![\tt f=(c)/(\lambda)\\\\f=(3.10^8~m/s)/(4.10^(-7)m)\\\\f=\boxed{\bold{7.5.10^(14)}/s}](https://img.qammunity.org/2021/formulas/chemistry/high-school/46cqdl3dvj834bn11hj1hwtexpzwyog18c.png)