15.1k views
1 vote
Light of wavelength 400 nm falls on a metal surface having a work function 1.70 eV. What is the maximum kinetic energy of the photoelectrons emitted from the metal?

a. 4.52 eV
b. 3.11 ev
c. 141 eV
d. 2.82 eV
e. 1.70 eV

1 Answer

3 votes

Answer:

Ke = 1.41 eV

Step-by-step explanation:

We know that

h = 6.626 x 10⁻²⁴

c = 3 x 10⁸

λ = 4 x 10⁻⁹ x 1.6 x 10⁻¹⁹

Computation:

Ke = [hc / λ] - w

Ke = [(6.626 x 10⁻²⁴)(3 x 10⁸) / (4 x 10⁻⁹ x 1.6 x 10⁻¹⁹)] - 1.70

Ke = 1.41 eV

User Mario GS
by
7.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.