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Help!!

A 30-N force is applied to a 4-kg object to move it with a constant

velocity of 2 m/s across a level surface. The coefficient of friction

between the object and the surface is approximately (Use the

approximation: g - 10 m/s/s.)


A 0.20

B O 0.50

C 0.55

D 0.75

User Agnaramon
by
8.3k points

1 Answer

3 votes

Answer:


\mu=0.75

Step-by-step explanation:

Given that,

Force acting on an object, F = 30 N

Mass of the object, m = 4 kg

It is moving with a constant velocity of 2 m/s across a level surface.

We need to find the coefficient of friction between the object and the surface. Let it is μ. Force in terms of coefficient of friction is given by :

F = μ N, Where N is normal force, N = mg


\mu=(F)/(mg)\\\\\mu=(30)/(4* 10)\\\\\mu=0.75

So, the coefficient of friction between the object and the surface is 0.75.

User Richard De Ree
by
8.2k points

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