Answer:
d. the coefficient of static friction is greater than the coefficient of kinetic friction.
Step-by-step explanation:
The magnitude of the for required to be applied to the carton is given as equal to the frictional force of between the carton and the surface. So, when the carton is at rest:
F = μs*W
and when the carton is in motion:
F = μk*W
where,
F = Force Required
μs = coefficient of static friction
μk = coefficient of kinetic friction
W = Weight of Carton
Since, the weight is constant. Therefore, for the increase in the force required to move the carton at rest than the force required to keep pushing the carton in velocity, the coefficient of static friction must be greater than the coefficient of kinetic friction. Therefore, the correct option is:
d. the coefficient of static friction is greater than the coefficient of kinetic friction.