Question

A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what will be the volume (in L) of the balloon if 0.80 moles of gas are added?

Answer 1

We know, when temperature and pressure is constant :

`(V_1)/(n_1)=(V_2)/(n_2)` ....1)

`n_1 = 3\ moles,\ V_1 = 1.50\ L`

`n_2 = 3 + 0.80 = 3.80 \ moles`

Let, final volume is
`V_2`.

Putting all values in equation 1), we get :

`(V_1)/(n_1)=(V_2)/(n_2)\\\\(1.50)/(3)=(V_2)/(3.80)\\\\V_2 = (1.50* 3.80)/(3)\\\\V_2 = 1.9\ L`

Therefore, volume (in L) of the balloon if 0.80 moles of gas are added is 1.9 L.

Hence, this is the required solution.