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A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what will be the volume (in L) of the balloon if 0.80 moles of gas are added?

User Zuim
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1 Answer

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We know, when temperature and pressure is constant :


(V_1)/(n_1)=(V_2)/(n_2) ....1)


n_1 = 3\ moles,\ V_1 = 1.50\ L


n_2 = 3 + 0.80 = 3.80 \ moles

Let, final volume is
V_2.

Putting all values in equation 1), we get :


(V_1)/(n_1)=(V_2)/(n_2)\\\\(1.50)/(3)=(V_2)/(3.80)\\\\V_2 = (1.50* 3.80)/(3)\\\\V_2 = 1.9\ L

Therefore, volume (in L) of the balloon if 0.80 moles of gas are added is 1.9 L.

Hence, this is the required solution.

User Ory Band
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