Question

A skateboarder skates down a ramp for 3 seconds. If his initial velocity was 0.8 m/s and · his final velocity was 7 m/s, what was his acceleration?

Answer 1

The acceleration of the skateboarder is 2.067 m/s²

Step-by-step explanation:

Given;

initial velocity of the skateboarder, u = 0.8 m/s

final velocity of the skateboarder, v = 7 m/s

time of motion, t = 3 s

The acceleration of the skateboarder is given as;

`a = (v-u)/(t)\\\\a = (7-0.8)/(3)\\\\a = 2.067 \ m/s^2`

Therefore, the acceleration of the skateboarder is 2.067 m/s²