Question

A 62Kg rock climber is attached to a rope that is allowing him to hang horizontally with his feet against the wall. The tension of the rope is 7.1x10^2 N, and the rope makes an angle of 32 degrees with the horizontal. Determine the force exerted by the wall on the climber's feet? I need some help with understanding the problem through a FBD as well as how I will find the x and y components. Thank You !

Answer 1

R= 602 .11 N

Step-by-step explanation:

The horizontal component of tension T will give reaction of the wall and the vertical component of T will balance the weight of of the climber .

T cos32 = R

710 x .848 = R

R= 602 .11 N .