Question

Enter the ordered pair for the vertices for (Ry-axis ○ T(2, 0))(QRST).

Answer 1

The answer is:

`Q' = (-3, 3)\\\\R' = (-5, -3)\\\\S' = (-2, -2)\\\\T' = (0, 1)\\\\`

Explanation:

All vertices of its quadrilateral were co-ordinated;

`T(-2, 1), \ Q(1, 3), \ S(0, -2), \ R(3, -3)` Therefore, we first undertake the operation correct:
`T(2, 0) \ QRST`, there;

`T(2, 0) \ QRST`
`\to T(-2 + 2, 1), \ Q(1 + 2, 3), \ S(0 + 2, -2), \ R(3 + 2, -3)`

`T(2, 0) \ QRST`
`\to T(0, 1), \ Q(3, 3), \ S(2, -2), \ R(5, -3)`

A preimage (x, y) will be the image in the next phase R-y-axis reflecting mostly on the y-axis (-x, y) and we've got it;

R y-axis
`(T(0, 1), \ Q(3, 3), \ S(2, -2), \ R(5, -3)) = \ T'(0, 1), \ Q'(-3, 3), \ S'(-2, -2), \ R'(-5, -3)`From which we get
`(Ry-axis \ T(2, 0)) \ (QRST = T'(0, 1), \ Q'(-3, 3), \ S'(-2, -2),\ R'(-5,-3).`