Question

Your mather bougth 20 kilos of mangoes and atis combined. Mango is P 60.00per kilos and atis is P 40.00 per kilos.If she paod P 1000.00 for 20 kilos, how many kilos of each kind mather bought A.)Ifx is number of kilos mango and number of kilos of atis then the eguation is ? B.) Eguation for the cost of fruits. C.) The system of eguations are ? D.) Solve by any method. E.) Check if your result will satisfy the problem.

Answer 1

What is it?

Explanation:

Answer 2

A)
`x+y=20`

B) Cost function is:
`3x+2y = 50`

C)
`x+y=20`,
`3x+2y = 50`

D)
`x=10, y=10`

E) Yes, the result satisfies the equations.

Explanation:

Let number of kilos of mango bought =
`x`

Let number of kilos of atis bought =
`y`

Total number of kilos bought = 20

A)
`x+y=20`

Cost of mango per kg = 60

Cost of mango for
`x` kg =
`60x`

Cost of atis per kg = 40

Cost of mango for
`y` kg =
`40y`

Total cost is: Cost of mango + Cost of atis = 1000

B) Cost function is:

`60x+40y=1000\\\Rightarrow 3x+2y = 50 ...... (2)`

C) System of equations are:

`x+y=20` ...... (1)

`3x+2y = 50`...... (2)

D) Using elimination method:

Multiplying equation (1) with 2 and subtracting from (2):

`x = 10`

By equation (1):

`\Rightarrow y =10`

E) Putting both the values in LHS of equation (1):

10+10 = 20 = RHS

Putting both the values in LHS of equation (2):

`3* 10 +2* 10` = 50 = RHS

Yes, the result satisfies the equations.