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A motobike's tire rotates with a constant angular speed of 62.8 rad/s. The radius of a tire is 30cm. Assuming that no slipping occurs, the number of revolutions of the tire in one second is: a. 12.6 b.
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A motobike's tire rotates with a constant angular speed of 62.8 rad/s. The radius of a tire is 30cm. Assuming that no slipping occurs, the number of

revolutions of the tire in one second is:

a.
12.6
b.
20
C.
18.8
d.
10

User Omg
by
4.7k points

1 Answer

1 vote

Answer:

10

Step-by-step explanation:

Given that :

Angular speed (w) = 62.8 rad/s

Radius of tire (r) = 30 cm

Number of revolutions per second :

s = 2πr

s = 2π * 0.3 = 1.8849555

The number or revolutions per second :

θ = s / r

θ = 1.884955 / 0.3

θ = 6.283185 rad

Number of revolutions per second :

62.8 / 6.283185

= 9.9949309

= 10

User Letthefireflieslive
by
4.7k points
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