Question

Question 5
What is a value of b will cause 27x^2+ bx +3 = 0 to have one real solution?

Answer 1

The values of b are
`\mathbf{b=\pm18}`

Explanation:

We need to find the value of b will cause
`27x^2+ bx +3 = 0` to have one real solution.

If it has one real solution, the discriminant is zero.

The formula of discriminant is:
`b^2-4ac`

In our case:
`b^2-4ac=0`

We have a=27, b=b and c=3

Putting values to find b

`b^2-4ac=0\\b^2-4(27)(3)=0\\b^2-324=0\\b^2=324\\Taking \ square root \ on \ both \ sides\\√(b^2)=√(324)\\b=\pm18`

So, the values of b are
`\mathbf{b=\pm18}`