Question

1. A gas at 116 kPa and 303 K fills a container at 2.0 x 105 L. If the temperature changes to 293 K, What is the new pressure?

Answer 1

P₂ = 112.17 KPa

Step-by-step explanation:

Given data:

Initial pressure = 116 KPa

Initial temperature = 303 K

Final temperature = 293 L

Final pressure = ?

Volume= constant

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

116 KPa / 303 K = P₂/293 K

P₂ = 116 KPa × 293 K / 303 K

P₂ = 33988 KPa. K / 303 K

P₂ = 112.17 KPa