Question

Need help.... please...

Answer 1

The function
`f(x)= x^3-\mathbf{2}x^2-\mathbf{8}x`

Explanation:

The zeros of the polynomial are: -2,4,0

We can write them as

x=-2, x=4, x=0

or

x+2=0,x-4=0,x=0

Multiplying all terms:

`(x+2)(x-4)(x)\\=((x-4)+2(x-4))(x)\\=x^2-4x+2x-8)x\\=(x^2-2x-8)x\\=x^3-2x^2-8x`

So, the function
`f(x)= x^3-\mathbf{2}x^2-\mathbf{8}x`