Question

PLEASE HELP

Solve for x 9^(x+2)=27^(8)

Answer 1

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`{9}^((x + 2)) = {27}^(8) \\`

`( { {3}^(2) })^(x + 2) = ({ {3}^(3) })^(8)`

`{3}^(2 * (x + 2)) = {3}^(3 * 8)`

`{3}^(2(x + 2)) = {3}^(24)`

Thus :

`2(x + 2) = 24`

Divide sides by 2

`(2(x + 2))/(2) = (24)/(2) \\`

`x + 2 = 12`

Subtract sides 2

`x + 2 - 2 = 12 - 2`

`x = 10`

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Answer 2

I believe the answer is x=10

Hope this is correct! :)