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Enter the equation in slope-intercept form. Then graph the line described by the equation.

5x + y = 1
Slope-intercept form is (select)

5x +y = 1

2 Answers

1 vote

Answer:

y = 1 -5x

Explanation:

You have to get y by itself. So first you move 5x to the other side but since it’s positive you have to make it negative so it canceled out.

User YellowBlue
by
5.6k points
3 votes

Hi there!


\large\boxed{y = -5x + 1}

5x + y = 1

Arrange into slope-intercept form (y = mx + b):

Subtract both sides by -5x to isolate y:

5x - 5x + y = 1 - 5x

y = 1 - 5x

Rearrange:

y = -5x + 1

Graph the equation by finding corresponding x and y values:

X Y

0 1

1 -4

2 -9

-1 6

-2 11

**Equation graphed below**

Enter the equation in slope-intercept form. Then graph the line described by the equation-example-1
User M Waz
by
6.2k points