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Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).

1 Answer

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Answer:


P(x,y) = (0,(11)/(5))

Explanation:

Given


A = (-2,1)


B = (3,4)


m:n = 2:3

Required

Determine the coordinates of P

The coordinate of a point when divided into ratio is:


P(x,y) = ((mx_2 + nx_1)/(m + n),(my_2 + ny_1)/(m + n))

Where


(x_1,y_1) = (-2,1)


(x_2,y_2) = (3,4)


m:n = 2:3

This gives:


P(x,y) = ((2 * 3 + 3 * -2)/(2 + 3),(2 * 4 + 3 * 1)/(2 + 3))


P(x,y) = ((6 - 6)/(5),(8 + 3)/(5))


P(x,y) = ((0)/(5),(11)/(5))


P(x,y) = (0,(11)/(5))

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