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Ns

2014
x ft
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Ns 2014 x ft Solve for Write your answers as a simplified radical and a decimal rounded-example-1

2 Answers

5 votes
1092829


2928392&2919292
User Chris Schmitz
by
7.2k points
3 votes

The solutions to the quadratic equation x^2 + 20 = 0 are complex numbers: x1 = 2√5i and x2 = -2√5i, approximately equal to 4.47i and -4.47i, respectively.

Use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation. In this case, a = 1, b = 0, and c = 20. Substituting these values, we get:

x = (-0 ± √(0^2 - 4 * 1 * 20)) / 2 * 1

x = (± √(-80)) / 2

Simplify the expression:

x = ± √(-80)

Since the square root of a negative number is imaginary, we can express it as √-80 = 4√5i

Separate the real and imaginary parts:

x = ± (2√5i)

Therefore, the solutions are:

x1 = 2√5i

x2 = -2√5i

Decimal approximations:

x1 ≈ 4.47i

x2 ≈ -4.47i

The solutions to the equation x^2 + 20 = 0 are x1 = 2√5i and x2 = -2√5i, which can be approximated decimally as x1 ≈ 4.47i and x2 ≈ -4.47i.

User Sangram Jadhav
by
6.6k points