Question

Find f'(x) for f(x) = -8x2-5x-4

Thank you :)

Answer 1

Explanation:

Use the constant, constant multiple, and power rules for derivatives: bring down the exponent and multiply it by the constant, then replace it with an exponent that is 1 less than what it was. The derivative of

`f(x)=-8x^2-5x-4` would look like this:

`f'(x)=-8(2)x^1-5-0` simplifying to

`f'(x)=-16x-5`