Question

What equation is graphed in this figure?

A. y−4=−13(x+2)

B. y−3=13(x+1)

C. y+2=−3(x−1)

D. y−5=3(x−1)

Answer 1

c.
`y + 2 = -3(x - 1)`

Explanation:

By using a point on the line and the slope, we can determine the equation, in point-slope form, that is graphed in the figure.

Using two points, (1, -2) and (0, 1),

`slope (m) = (y_2 - y_1)/(x_2 - x_1) = (1 -(-2))/(0 - 1) = (3)/(-1) = -3`

m = -3

Using a point, (1, -2) and the slope (m), we can create an equation for the graph in point-slope form, by substituting x1 = 1, y1 = -2 and m = -3 in
`y - y_1 = m(x - x_1)`.

Thus, we would have:

`y -(-2) = -3(x - 1)`

`y + 2 = -3(x - 1)`

The equation that is graphed in the figure is:

✔️
`y + 2 = -3(x - 1)`