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Indicate the equation of the given line in standard form, writing the answer below.

The line that is the perpendicular bisector of the segment whose endpoints are R(-1,6) and S(5,5).

User Leela
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1 Answer

12 votes
12 votes

Answer:
y-(11)/(2)=6(x-2)

Explanation:

For it to bisect the segment, we need to find the midpoint.

The midpoint is
\left((-1+5)/(2), (6+5)/(2) \right)=\left(2, (11)/(2) \right).

Now, for it to be perpendicular, we need to use the fact that perpendicular lines have slopes that are negative reciprocals of each other.

The slope of the given segment is
(6-5)/(-1-5)=-(1)/(6), so the slope of the perpendicular bisector is 6.

Thus, the equation of the line in point-slope form is
\boxed{y-(11)/(2)=6(x-2)}

Indicate the equation of the given line in standard form, writing the answer below-example-1
Indicate the equation of the given line in standard form, writing the answer below-example-2
User Mahmoud Hboubati
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2.7k points