A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate acceleration.

asked Jul 24, 2021 13.7k views

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A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate
acceleration.

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Answer:

Acceleration = 3m/s^2

Vf= 0 Vi =35m/s t= 13s

Step-by-step explanation:

$Acceleration = (Change in velocity)/(Change in time)\\ = (35m/s)/(13s)\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2$

Jlanik answered Jul 29, 2021

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