Answer:
![\displaystyle \vec u_A=(4)/(5)\hat i +(3)/(5)\hat j](https://img.qammunity.org/2021/formulas/physics/high-school/upd2g2whmmze6fmmm7xlmu4an3ccrdclb1.png)
Step-by-step explanation:
Unit Vector
The unit vector associated with a given vector
is another vector pointing in the same direction of
and with magnitude 1.
The unit vector can be calculated as follows:
![\displaystyle \vec u_a=(\vec a )/(||\vec a ||)](https://img.qammunity.org/2021/formulas/physics/high-school/p6sztqw75fbu7ni8zsv6vbqxaunypo652j.png)
Where
is the magnitude of the vector.
If
is given as:
![\vec a = x\hat i +y\hat j](https://img.qammunity.org/2021/formulas/physics/high-school/y1k6knsi5g99hra078xjbr2wzljg1ex3vd.png)
The magnitude of the vector is:
![=√(x^2+y^2)](https://img.qammunity.org/2021/formulas/physics/high-school/mttf525sikb7ia9ujfa3kdxrzpk7hk6bx0.png)
We have:
![\vec A=4\hat i +3\hat j](https://img.qammunity.org/2021/formulas/physics/high-school/g5h2lan97jqge209y48db2p71c9yvkymck.png)
![=√(4^2+3^2)=√(25)=5](https://img.qammunity.org/2021/formulas/physics/high-school/zfdgnqfrpyntymfvr9iuskmrdjbwfkcdmc.png)
Thus the unit vector is:
![\displaystyle \vec u_A=(4\hat i +3\hat j )/(5)](https://img.qammunity.org/2021/formulas/physics/high-school/y85fs6kl46ims6tcp7vg8if7z2110z54l1.png)
Simplifying:
![\mathbf{\displaystyle \vec u_A=(4)/(5)\hat i +(3)/(5)\hat j}](https://img.qammunity.org/2021/formulas/physics/high-school/amj7px24zn4dtcng70y29hjtjetg537tug.png)